4-(400/(x-8)^2)

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Solution for 4-(400/(x-8)^2) equation:


D( x )

(x-8)^2 = 0

(x-8)^2 = 0

(x-8)^2 = 0

x-8 = 0 // + 8

x = 8

x in (-oo:8) U (8:+oo)

4-(400/((x-8)^2)) = 0

4-400*(x-8)^-2 = 0

4-400/((x-8)^2) = 0

(4*(x-8)^2)/((x-8)^2)-400/((x-8)^2) = 0

4*(x-8)^2-400 = 0

4*x^2-64*x-144 = 0

4*x^2-64*x-144 = 0

4*(x^2-16*x-36) = 0

x^2-16*x-36 = 0

DELTA = (-16)^2-(-36*1*4)

DELTA = 400

DELTA > 0

x = (400^(1/2)+16)/(1*2) or x = (16-400^(1/2))/(1*2)

x = 18 or x = -2

4*(x+2)*(x-18) = 0

(4*(x+2)*(x-18))/((x-8)^2) = 0

(4*(x+2)*(x-18))/((x-8)^2) = 0 // * (x-8)^2

4*(x+2)*(x-18) = 0

( 4 )

4 = 0

x belongs to the empty set

( x+2 )

x+2 = 0 // - 2

x = -2

( x-18 )

x-18 = 0 // + 18

x = 18

x in { -2, 18 }

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